
Given the following resistor network, the resistances are arranged as shown:
From the given circuit:
The resistances between points A, B, C, and D are:
\( 6 \, \Omega \) between A and C, \( 10 \, \Omega \) between B and C, \( 8 \, \Omega \) between C and D, \( 5 \, \Omega \) between B and D, and \( 4 \, \Omega \) between A and D.
First, combine the resistances in parallel and series:
Combine the \( 15 \, \Omega \) resistors in series between points A, C, and B. After the simplification, we get:
\( R_{\text{eq}} = 6 \, \Omega + 5 \, \Omega + 8 \, \Omega = 19 \, \Omega \)
Thus, the correct answer is:
\( R_{\text{eq}} = 19 \, \Omega \)

Thus the correct answer is 19 $\Omega$.

The equivalent resistance between the points \(A\) and \(B\) in the given circuit is \[ \frac{x}{5}\,\Omega. \] Find the value of \(x\). 
A Wheatstone bridge is initially at room temperature and all arms of the bridge have same value of resistances \[ (R_1=R_2=R_3=R_4). \] When \(R_3\) resistance is heated, its resistance value increases by \(10%\). The potential difference \((V_a-V_b)\) after \(R_3\) is heated is _______ V. 
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 