The given equilibrium is:
\(\text{Cr}_2\text{O}_7^{2-} \rightleftharpoons 2\text{CrO}_4^{2-}\)
This is a classic example of a chemical equilibrium that is sensitive to the pH of the solution. Let's analyze the situation to understand why this equilibrium shifts in different pH conditions:
Conclusion: Since the equilibrium shifts to the right in a basic medium (as OH- ions neutralize H+ ions), the correct answer is a basic medium.
The given equilibrium reaction is:
\(\mathrm{Cr_2O_7^{2-}} \rightleftharpoons 2\mathrm{CrO_4^{2-}}\)
This equilibrium can be affected by the pH of the solution. Specifically, this reaction is an example of how pH influences equilibrium according to Le Chatelier's principle.
Explanation:
Justification of the Correct Answer (Basic Medium):
In a basic medium, the equilibrium will shift towards the formation of chromate ions, \(\mathrm{CrO_4^{2-}}\), moving the equilibrium to the right. This is in accordance with Le Chatelier's principle, as the system adjusts to reduce the effect of the added base (hydroxide ions).
Conclusion:
Thus, the equilibrium \(\mathrm{Cr_2O_7^{2-}} \rightleftharpoons 2\mathrm{CrO_4^{2-}}\) is shifted to the right in a basic medium.
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 