The given equilibrium is:
\(\text{Cr}_2\text{O}_7^{2-} \rightleftharpoons 2\text{CrO}_4^{2-}\)
This is a classic example of a chemical equilibrium that is sensitive to the pH of the solution. Let's analyze the situation to understand why this equilibrium shifts in different pH conditions:
Conclusion: Since the equilibrium shifts to the right in a basic medium (as OH- ions neutralize H+ ions), the correct answer is a basic medium.
The given equilibrium reaction is:
\(\mathrm{Cr_2O_7^{2-}} \rightleftharpoons 2\mathrm{CrO_4^{2-}}\)
This equilibrium can be affected by the pH of the solution. Specifically, this reaction is an example of how pH influences equilibrium according to Le Chatelier's principle.
Explanation:
Justification of the Correct Answer (Basic Medium):
In a basic medium, the equilibrium will shift towards the formation of chromate ions, \(\mathrm{CrO_4^{2-}}\), moving the equilibrium to the right. This is in accordance with Le Chatelier's principle, as the system adjusts to reduce the effect of the added base (hydroxide ions).
Conclusion:
Thus, the equilibrium \(\mathrm{Cr_2O_7^{2-}} \rightleftharpoons 2\mathrm{CrO_4^{2-}}\) is shifted to the right in a basic medium.
Let \( \alpha = \dfrac{-1 + i\sqrt{3}}{2} \) and \( \beta = \dfrac{-1 - i\sqrt{3}}{2} \), where \( i = \sqrt{-1} \). If
\[ (7 - 7\alpha + 9\beta)^{20} + (9 + 7\alpha - 7\beta)^{20} + (-7 + 9\alpha + 7\beta)^{20} + (14 + 7\alpha + 7\beta)^{20} = m^{10}, \] then the value of \( m \) is ___________.