Question:

The equation of the line passing through the point (5, 3, 2) and perpendicular to the lines \(\frac{x-2}{1}=\frac{y-3}{-1}=\frac{z-4}{1}\) and \(\frac{x-1}{2}=\frac{y-1}{1}=\frac{z+1}{0}\) is

Updated On: Sep 15, 2024
  • \(\frac{x-5}{-1}=\frac{y-3}{2}=\frac{z-2}{3}\)
  • \(\frac{x+1}{5}=\frac{y-2}{3}=\frac{z-3}{2}\)
  • \(\frac{x-5}{1}=\frac{y-3}{-1}=\frac{z-2}{1}\)
  • \(\frac{x-5}{2}=\frac{y-3}{1}=\frac{z-2}{0}\)
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The Correct Option is A

Solution and Explanation

The correct option is (A) : \(\frac{x-5}{-1}=\frac{y-3}{2}=\frac{z-2}{3}\).
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