Question:

The equation of the line passing through the point (5, 3, 2) and perpendicular to the lines x21=y31=z41\frac{x-2}{1}=\frac{y-3}{-1}=\frac{z-4}{1} and x12=y11=z+10\frac{x-1}{2}=\frac{y-1}{1}=\frac{z+1}{0} is

Updated On: Sep 14, 2024
  • x51=y32=z23\frac{x-5}{-1}=\frac{y-3}{2}=\frac{z-2}{3}
  • x+15=y23=z32\frac{x+1}{5}=\frac{y-2}{3}=\frac{z-3}{2}
  • x51=y31=z21\frac{x-5}{1}=\frac{y-3}{-1}=\frac{z-2}{1}
  • x52=y31=z20\frac{x-5}{2}=\frac{y-3}{1}=\frac{z-2}{0}
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The Correct Option is A

Solution and Explanation

The correct option is (A) : x51=y32=z23\frac{x-5}{-1}=\frac{y-3}{2}=\frac{z-2}{3}.
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