Question:
The equation of straight line which passes through the point (a cos3θ, a sin3θ) and perpendicular to x secθ+y cosecθ = a is
The equation of straight line which passes through the point (a cos3θ, a sin3θ) and perpendicular to x secθ+y cosecθ = a is
Updated On: Apr 17, 2024
- \(\frac{x}{a}+\frac{y}{b}=a\ \cos\theta\)
- x cosθ - y sinθ = a cos2θ
- x cosθ + y sinθ = a cos2θ
- x cosθ - y sinθ = -a cos2θ
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The Correct Option is B
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The correct answer is () :
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