Question

The enthalpy change for the evaporation of a liquid at its boiling point 127°C is +40.32 $kJmol^{-1}$. What is the value of internal energy change for the above process at 127°C? (R=8.3 $JK^{-1}mol^{-1}$)

• A. -37.0 $kJmol^{-1}$
• B. +37.0 $kJmol^{-1}$
• C. +43.64 $kJmol^{-1}$
• D. +43.0 $kJmol^{-1}$
• E. -43.0 $kJmol^{-1}$

Answer 1

The Correct Option is A

The correct option is (A) : -37.0 $kJmol^{-1}$