To determine the correct enol form of ethyl-3-oxobutanoate, we analyze the compound's tendency to undergo keto-enol tautomerism.
Step-by-step Analysis:
1. Structure of Ethyl-3-oxobutanoate: This is a β-keto ester with a ketone at the 3-position and an ester at the 1-position. Such compounds readily exhibit keto-enol tautomerism.
2. Enol Formation: The hydrogen at the alpha carbon (between the ester and ketone groups) is acidic and can be removed to form a double bond with the carbon adjacent to the ketone. The carbonyl oxygen of the ketone becomes an OH group.
3. Stability of Enol: The most stable enol is typically the one where the OH group is hydrogen bonded to the ester oxygen, forming a six-membered ring. Additionally, conjugation between the C=C bond and the ester group enhances stability.
4. Evaluating the Options: Among the given images, the correct enol form is the one where:
- A C=C bond is formed between the alpha and carbonyl carbon
- The ketone oxygen is converted into an OH group
- Intramolecular hydrogen bonding and conjugation are possible
Conclusion: The correct enol form is shown in the third image.
Number of \( ^1H \) NMR signals observed for the following compound is .............
A quantity \( X \) is given by: \[ X = \frac{\epsilon_0 L \Delta V}{\Delta t} \] where:
- \( \epsilon_0 \) is the permittivity of free space,
- \( L \) is the length,
- \( \Delta V \) is the potential difference,
- \( \Delta t \) is the time interval.
The dimension of \( X \) is the same as that of: