Step 1: The energy equivalent \( E \) of mass \( m \) is given by Einstein's equation: \[ E = mc^2 \]
where:
- \( m = 1 \, {g} = 1 \times 10^{-3} \, {kg} \),
- \( c = 3 \times 10^8 \, {m/s} \).
Step 2: Substitute the values into the equation: \[ E = (1 \times 10^{-3}) \times (3 \times 10^8)^2 = 9 \times 10^{13} \, {J} \]
Thus, the energy equivalent of 1 g of substance is \( 9 \times 10^{13} \, {J} \).
For the reaction:
\[ 2A + B \rightarrow 2C + D \]
The following kinetic data were obtained for three different experiments performed at the same temperature:
\[ \begin{array}{|c|c|c|c|} \hline \text{Experiment} & [A]_0 \, (\text{M}) & [B]_0 \, (\text{M}) & \text{Initial rate} \, (\text{M/s}) \\ \hline I & 0.10 & 0.10 & 0.10 \\ II & 0.20 & 0.10 & 0.40 \\ III & 0.20 & 0.20 & 0.40 \\ \hline \end{array} \]
The total order and order in [B] for the reaction are respectively: