The energy of an electron in the \( n \)-th orbit of a hydrogen-like atom is given by the formula:
\( E_n = -2.18 \times 10^{-18} \times \frac{Z^2}{n^2} \)
For He⁺, \( Z = 2 \) (atomic number of helium) and \( n = 1 \) (first orbit):
\( E = -2.18 \times 10^{-18} \times \frac{2^2}{1^2} \)
\( E = -2.18 \times 10^{-18} \times 4 = -8.72 \times 10^{-18} \, \text{J} \)
Thus, the energy associated with the first orbit of He⁺ is \( -8.72 \times 10^{-18} \, \text{J} \).