Question:

The end points of a uniform wire are joined to a cell of emf $ E $ and internal resistance $ r $. Starting from the midpoint of the wire and moving in the direction of the current, the potential $ V(x) $ is measured at every point till the midpoint is reached again. The plot that represents the potential $ V $ against distance $ x $ moved from mid point is

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In circuits with internal resistance, the potential varies non-linearly across the wire, and the change in potential depends on the distance from the midpoint of the wire.
Updated On: May 9, 2025
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The Correct Option is B

Solution and Explanation

In this circuit, the potential \( V(x) \) will vary in a non-linear fashion as the current flows through the wire. The potential decreases from the midpoint of the wire toward the negative terminal of the cell and increases towards the positive terminal due to the internal resistance of the cell. The graph of \( V(x) \) versus \( x \) will show a decrease followed by an increase, representing the potential drop and rise.
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