Question:
The enamel present on teeth becomes much harder due to the conversion of hydroxyapatite into fluorapatite. What are \( X \) and \( Y \)?
The enamel present on teeth becomes much harder due to the conversion of hydroxyapatite into fluorapatite. What are \( X \) and \( Y \)?
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Fluoride strengthens enamel by converting hydroxyapatite into fluorapatite.
Updated On: Mar 24, 2025
- \( X = {Ca(OH)}_2, Y = {CaF}_2 \)
- \( X = {Ca(OH)}_2, Y = {CaCl}_2 \)
- \( X = {Ca(OH)}_2, Y = {NaCl} \)
- \( X = {CaO}, Y = {CaCl}_2 \)
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The Correct Option is A
Solution and Explanation
Step 1: Understanding Tooth Enamel Hardening
- Hydroxyapatite: \( {Ca}_5({PO}_4)_3{OH} \)
- Fluoride treatment replaces OH⁻ with F⁻, forming fluorapatite, which is stronger.
\[ 3{Ca}_5({PO}_4)_3{OH} + F^- \rightarrow 3{Ca}_5({PO}_4)_3{F} \]
- \( X = {Ca(OH)}_2 \) contributes OH⁻.
- \( Y = {CaF}_2 \) provides F⁻.
- Hydroxyapatite: \( {Ca}_5({PO}_4)_3{OH} \)
- Fluoride treatment replaces OH⁻ with F⁻, forming fluorapatite, which is stronger.
\[ 3{Ca}_5({PO}_4)_3{OH} + F^- \rightarrow 3{Ca}_5({PO}_4)_3{F} \]
- \( X = {Ca(OH)}_2 \) contributes OH⁻.
- \( Y = {CaF}_2 \) provides F⁻.
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