Step 1: Median calculation
The median of the dataset is the middle element. Since the dataset has 5 elements, the median will be the third element in the ordered set. Thus, \( a = 3 \) because the median is 3, and it corresponds to the third element.
Step 2: Mean calculation
The mean of the dataset is the sum of the elements divided by the number of elements. We are told that the mean is 3, so we can use the formula: \[ {Mean} = \frac{-5 + 1 + a + 5 + b}{5} = 3. \] Substituting \( a = 3 \) into the equation: \[ \frac{-5 + 1 + 3 + 5 + b}{5} = 3. \] Simplifying the equation: \[ \frac{4 + b}{5} = 3, \] \[ 4 + b = 15, \] \[ b = 11. \] Thus, the value of \( b \) is 11.
For the following ten angle observations, the standard error of the mean angle is given as 2cm arcsecond (rounded off to 2 decimal places).
25$^\circ$40'12'' | 25$^\circ$40'14'' | 25$^\circ$40'16'' | 25$^\circ$40'18'' | 25$^\circ$40'09'' |
25$^\circ$40'15'' | 25$^\circ$40'10'' | 25$^\circ$40'13'' | 25$^\circ$40'15'' | 25$^\circ$40'18'' |
The residual error in a measurement comprises a bias of \( +0.08 \, {m} \) and a random component given by the following density function: \[ f(x) = \frac{1}{0.15 \sqrt{2\pi}} \exp\left( -\frac{x^2}{2 \cdot (0.15)^2} \right) \] For this system, the mean square error (MSE) is __________ m (rounded off to 2 decimal places).
The covariance matrix, \( \Sigma \), for the planar coordinates of a surveyed point is given as:
\[ \Sigma = \begin{bmatrix} 25 & 0.500 \\ 0.500 & 100 \end{bmatrix} \quad \text{(in mm}^2\text{)} \] The coefficient of correlation is __________ (rounded off to 2 decimal places).
The plot of \( \log_{10} ({BMR}) \) as a function of \( \log_{10} (M) \) is a straight line with slope 0.75, where \( M \) is the mass of the person and BMR is the Basal Metabolic Rate. If a child with \( M = 10 \, {kg} \) has a BMR = 600 kcal/day, the BMR for an adult with \( M = 100 \, {kg} \) is _______ kcal/day. (rounded off to the nearest integer)
For the RLC circuit shown below, the root mean square current \( I_{{rms}} \) at the resonance frequency is _______amperes. (rounded off to the nearest integer)
\[ V_{{rms}} = 240 \, {V}, \quad R = 60 \, \Omega, \quad L = 10 \, {mH}, \quad C = 8 \, \mu {F} \]
The frequency of the oscillator circuit shown in the figure below is _______(in kHz, rounded off to two decimal places).
Given: \( R = 1 \, k\Omega; R_1 = 2 \, k\Omega; R_2 = 6 \, k\Omega; C = 0.1 \, \mu F \)