Step 1: Median calculation
The median of the dataset is the middle element. Since the dataset has 5 elements, the median will be the third element in the ordered set. Thus, \( a = 3 \) because the median is 3, and it corresponds to the third element.
Step 2: Mean calculation
The mean of the dataset is the sum of the elements divided by the number of elements. We are told that the mean is 3, so we can use the formula: \[ {Mean} = \frac{-5 + 1 + a + 5 + b}{5} = 3. \] Substituting \( a = 3 \) into the equation: \[ \frac{-5 + 1 + 3 + 5 + b}{5} = 3. \] Simplifying the equation: \[ \frac{4 + b}{5} = 3, \] \[ 4 + b = 15, \] \[ b = 11. \] Thus, the value of \( b \) is 11.
Here are two analogous groups, Group-I and Group-II, that list words in their decreasing order of intensity. Identify the missing word in Group-II.
Abuse \( \rightarrow \) Insult \( \rightarrow \) Ridicule
__________ \( \rightarrow \) Praise \( \rightarrow \) Appreciate
The plot of \( \log_{10} ({BMR}) \) as a function of \( \log_{10} (M) \) is a straight line with slope 0.75, where \( M \) is the mass of the person and BMR is the Basal Metabolic Rate. If a child with \( M = 10 \, {kg} \) has a BMR = 600 kcal/day, the BMR for an adult with \( M = 100 \, {kg} \) is _______ kcal/day. (rounded off to the nearest integer)
For the RLC circuit shown below, the root mean square current \( I_{{rms}} \) at the resonance frequency is _______amperes. (rounded off to the nearest integer)
\[ V_{{rms}} = 240 \, {V}, \quad R = 60 \, \Omega, \quad L = 10 \, {mH}, \quad C = 8 \, \mu {F} \]