Step 1: Median calculation
The median of the dataset is the middle element. Since the dataset has 5 elements, the median will be the third element in the ordered set. Thus, \( a = 3 \) because the median is 3, and it corresponds to the third element.
Step 2: Mean calculation
The mean of the dataset is the sum of the elements divided by the number of elements. We are told that the mean is 3, so we can use the formula: \[ {Mean} = \frac{-5 + 1 + a + 5 + b}{5} = 3. \] Substituting \( a = 3 \) into the equation: \[ \frac{-5 + 1 + 3 + 5 + b}{5} = 3. \] Simplifying the equation: \[ \frac{4 + b}{5} = 3, \] \[ 4 + b = 15, \] \[ b = 11. \] Thus, the value of \( b \) is 11.
The coefficient of correlation of the above two data series will be equal to \(\underline{\hspace{1cm}}\)
\[\begin{array}{|c|c|} \hline X & Y \\ \hline -3 & 9 \\ -2 & 4 \\ -1 & 1 \\ 0 & 0 \\ 1 & 1 \\ 2 & 4 \\ 3 & 9 \\ \hline \end{array}\]
Identify the median class for the following grouped data:
\[\begin{array}{|c|c|} \hline \textbf{Class interval} & \textbf{Frequency} \\ \hline 5-10 & 5 \\ 10-15 & 15 \\ 15-20 & 22 \\ 20-25 & 25 \\ 25-30 & 10 \\ 30-35 & 3 \\ \hline \end{array}\]
The 12 musical notes are given as \( C, C^\#, D, D^\#, E, F, F^\#, G, G^\#, A, A^\#, B \). Frequency of each note is \( \sqrt[12]{2} \) times the frequency of the previous note. If the frequency of the note C is 130.8 Hz, then the ratio of frequencies of notes F# and C is:
Here are two analogous groups, Group-I and Group-II, that list words in their decreasing order of intensity. Identify the missing word in Group-II.
Abuse \( \rightarrow \) Insult \( \rightarrow \) Ridicule
__________ \( \rightarrow \) Praise \( \rightarrow \) Appreciate