In intrinsic semiconductors, the product of the electron concentration \( n_e \) and hole concentration \( n_h \) is equal to the square of the intrinsic carrier concentration \( n_i \): \[ n_e n_h = n_i^2 \] This relation holds because in an intrinsic semiconductor, the number of electrons is equal to the number of holes.
Thus, the correct answer is (A).
Match the following types of nuclei with examples shown:
Let \( I = \int_{-\frac{\pi}{4}}^{\frac{\pi}{4}} \frac{\tan^2 x}{1+5^x} \, dx \). Then: