



Given: A graph of electric potential \( V \) along the X-axis. We are to choose the correct graph of
electric field strength \( E \). Key Concept: Electric field is the negative gradient (slope) of electric potential: \[ E = -\frac{dV}{dx} \] - Where the potential decreases linearly, \( E \) is constant and negative. - Where the slope of \( V(x) \) increases, \( E \) becomes more negative. - Where the slope becomes less steep (towards flat), \( E \) approaches zero. - If slope changes sign, \( E \) changes sign.
Analyzing the given potential graph: - From left to right, the slope (negative of \( E \)) is: - Steep (large negative) - Moderate (less negative) - Flat (zero) - Positive slope (negative \( E \)), so field becomes positive So, \( E \) starts negative, increases toward zero, then becomes positive.
Correct Plot: The electric field graph that starts negative, increases, crosses zero, and becomes positive.
Two large plane parallel conducting plates are kept 10 cm apart as shown in figure. The potential difference between them is $ V $. The potential difference between the points A and B (shown in the figure) is: 
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): Net dipole moment of a polar linear isotropic dielectric substance is not zero even in the absence of an external electric field. Reason
(R): In absence of an external electric field, the different permanent dipoles of a polar dielectric substance are oriented in random directions.
In the light of the above statements, choose the most appropriate answer from the options given below:
A metallic ring is uniformly charged as shown in the figure. AC and BD are two mutually perpendicular diameters. Electric field due to arc AB to O is ‘E’ magnitude. What would be the magnitude of electric field at ‘O’ due to arc ABC? 

Which of the following statement(s) is/are correct about the given compound?
