Question:

The earth circles around the sun once a year. The work which would have to be done on the earth to bring it to rest relative to the sun is, (Ignore the rotation of earth about its own axis) given that the mass of the earth $=6 \times 10^{24}\, kg$ and distance between sun and earth is $1.5 \times 10^{8}\, km$)

Updated On: Jul 29, 2022
  • $2.7 \times {10}^{30}\,J$
  • $2.7\times {10}^{31}\, J$
  • $-2.7\times {10}^{33}\, J$
  • $+2.7 \times {10}^{33}\, J$
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The Correct Option is C

Solution and Explanation

$\omega =\frac{2 \pi}{T}$ $=\frac{2 \pi}{365 \times 24 \times 3600}$ $=1.99 \times 10^{-7}\, rad / s$ $W =K_{f}-K_{i}=0-\frac{1}{2} m v^{2} $ $(v=\omega R)$ $=\frac{1}{2} \times 6 \times 10^{24} \times\left(1.5 \times 10^{11} \times 1.99 \times 10^{-7}\right)^{2}$ $=-2.7 \times 10^{33}\, J$
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Questions Asked in AIIMS exam

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Concepts Used:

Work

Work is the product of the component of the force in the direction of the displacement and the magnitude of this displacement.

Work Formula:

W = Force × Distance

Where,

Work (W) is equal to the force (f) time the distance.

Work Equations:

W = F d Cos θ

Where,

 W = Amount of work, F = Vector of force, D = Magnitude of displacement, and θ = Angle between the vector of force and vector of displacement.

Unit of Work:

The SI unit for the work is the joule (J), and it is defined as the work done by a force of 1 Newton in moving an object for a distance of one unit meter in the direction of the force.

Work formula is used to measure the amount of work done, force, or displacement in any maths or real-life problem. It is written as in Newton meter or Nm.