Question:

A 10 kg object is lifted to a height of 5 meters. Calculate the work done in lifting the object.

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Work done is always calculated as the force applied over a distance. In gravitational work problems, the force is equal to the weight of the object, which is the product of mass and gravitational acceleration.
Updated On: Apr 18, 2025
  • \( 500 \, \text{J} \)
  • \( 100 \, \text{J} \)
  • \( 200 \, \text{J} \)
  • \( 150 \, \text{J} \)
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The Correct Option is A

Solution and Explanation

The work done in lifting an object is given by the formula: \[ W = F \times d \] Where: - \( W \) is the work done, - \( F \) is the force applied, - \( d = 5 \, \text{m} \) is the distance through which the object is lifted. The force applied is equal to the weight of the object, which is given by: \[ F = mg \] Where: - \( m = 10 \, \text{kg} \) is the mass of the object, - \( g = 9.8 \, \text{m/s}^2 \) is the acceleration due to gravity. Thus: \[ F = 10 \times 9.8 = 98 \, \text{N} \] Now, the work done is: \[ W = 98 \times 5 = 490 \, \text{J} \] Rounding off, the work done is approximately \( 500 \, \text{J} \).
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