Question

A 10 kg object is lifted to a height of 5 meters. Calculate the work done in lifting the object.

• A. \( 500 \, \text{J} \)
• B. \( 100 \, \text{J} \)
• C. \( 200 \, \text{J} \)
• D. \( 150 \, \text{J} \)

Hint:

Work done is always calculated as the force applied over a distance. In gravitational work problems, the force is equal to the weight of the object, which is the product of mass and gravitational acceleration.

Answer 1

The Correct Option is A

To calculate the work done in lifting an object, we use the formula for work done against gravity: 
\( W = m \cdot g \cdot h \)  
where \( W \) is the work done, \( m \) is the mass of the object, \( g \) is the acceleration due to gravity (approximately \( 9.8 \, \text{m/s}^2 \)), and \( h \) is the height. 
Given: 
\( m = 10 \, \text{kg} \) 
\( h = 5 \, \text{m} \) 
Substituting these values into the equation: 
\( W = 10 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 5 \, \text{m} \) 
\( W = 490 \, \text{J} \) 
The theoretical value \(490 \, \text{J}\) is close to the provided correct answer of \(500 \, \text{J}\). The options may reflect a rounding in the gravitational constant or other simplifications in exam questions. Thus, the most appropriate answer is \( 500 \, \text{J} \).