Question:

The drag force, \( F_D \), on a sphere due to a fluid flowing past the sphere is a function of viscosity, \( \mu \), the mass density, \( \rho \), the velocity of flow, \( V \), and the diameter of the sphere, \( D \). Pick the relevant (one or more) non-dimensional parameter(s) pertaining to the above process from the following list.

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When solving for non-dimensional parameters in fluid dynamics, always start by identifying the physical dimensions of the variables involved. Use Buckingham’s Pi Theorem to derive the dimensionless numbers that describe the process.
Updated On: Apr 3, 2025
  • \( \frac{F_D}{\rho V^2 D^2} \)
  • \( \frac{\rho F_D}{V^2 D^2} \)
  • \( \frac{\rho V D}{\mu} \)
  • \( \frac{\mu \rho}{V D} \)
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The Correct Option is A, C

Solution and Explanation

To solve for the non-dimensional parameters, we need to apply Buckingham’s Pi Theorem, which helps derive dimensionless parameters (Pi terms). Starting with the drag force equation: \[ F_D = F(D, V, \rho, \mu) \] We express the dimensions: \[ F_D = [M L T^{-2}], \quad \rho = [M L^{-3}], \quad V = [L T^{-1}], \quad \mu = [M L^{-1} T^{-1}] \] We substitute these into the drag force equation and apply the Buckingham’s Pi Theorem. After calculating, the resulting non-dimensional parameters are: \[ \pi_1 = \frac{F_D}{\rho V^2 D^2}, \quad \pi_2 = \frac{\rho V D}{\mu} \] Both expressions are dimensionless and represent the non-dimensional parameters related to the drag force on the sphere. 
Hence, the correct answers are (A) and (C).

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