In levelling between two points A and B on the opposite banks of a river, the readings are taken by setting the instrument both at A and B, as shown in the table. If the RL of A is 150.000 m, the RL of B (in m) is ....... (rounded off to 3 decimal places).
The height difference between two points (A and B) in levelling is calculated using the formula:
\[ H_{{avg}} = \frac{(H_1 - H_2) + (H_3 - H_4)}{2} \]
where:
From the problem statement:
Now, calculating the average height difference:
\[ H_{{avg}} = \frac{(1.8 - 1.35) + (1.45 - 0.95)}{2} \]
\[ H_{{avg}} = \frac{0.45 + 0.5}{2} = \frac{0.95}{2} = 0.475 \, \text{m} \]
Given that the RL of point A is 150.000 m, we calculate:
\[ \text{RL of B} = \text{RL of A} + H_{{avg}} \]
\[ = 150.000 + 0.475 = 150.475 \, \text{m} \]
Correct Answer: \( \mathbf{150.475} \) m (rounded to three decimal places).
Match the following in Column I with Column II.
A one-way, single lane road has traffic that consists of 30% trucks and 70% cars. The speed of trucks (in km/h) is a uniform random variable on the interval (30, 60), and the speed of cars (in km/h) is a uniform random variable on the interval (40, 80). The speed limit on the road is 50 km/h. The percentage of vehicles that exceed the speed limit is ........ (rounded off to 1 decimal place).