Question

The distribution function $f(E)$ for a photon gas is given by:

• A. $e^{-E / k_B T}$
• B. $\frac{E}{k_B T} e^{-E / k_B T}$
• C. $\frac{1}{e^{E / k_B T} - 1}$
• D. $\frac{1}{e^{-E / k_B T} + 1}$

Hint:

Photons obey Bose-Einstein distribution because they are bosons with zero chemical potential.

Answer 1

The Correct Option is C

Photon gas follows Bose-Einstein statistics. The occupation number distribution for bosons (such as photons) is given by:
$$f(E) = \frac{1}{e^{E / k_B T} - 1}$$