Question:

The displacement x x of a body varies with time as x=13t2+16t+2 x = -\frac{1}{3} t^2 + 16 t +2 , where x x is in metres and tt is in seconds. The time taken by the body to come to rest is

Updated On: Jun 14, 2022
  • 12s 12\,s
  • 24s 24\,s
  • 30s 30 \,s
  • 36s 36 \,s
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The Correct Option is B

Solution and Explanation

Displacement of a body,
x=13t2+16t+3  [v=dxdt]x = - \frac{1}{3} t^2 + 16 t + 3 \,\,[\because v = \frac{dx}{dt}]
From the question, v=0v = 0
or ddt(13t2+16t+3)=0\frac{d}{dt}( - \frac{1}{3} t^2 + 16 t + 3) = 0
or 23t+16+0=0 - \frac{2}{3}t + 16 + 0 = 0
or 23t=16-\frac{2}{3}t = - 16
or t=16×32=24s t = \frac{16 \times 3}{2} = 24\,s
So, time taken by the body to come to rest is 24s24 \,s.
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Questions Asked in AMUEEE exam

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Concepts Used:

Motion in a straight line

The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion. 

Types of Linear Motion:

Linear motion is also known as the Rectilinear Motion which are of two types:

  1. Uniform linear motion with constant velocity or zero acceleration: If a body travels in a straight line by covering an equal amount of distance in an equal interval of time then it is said to have uniform motion.
  2. Non-Uniform linear motion with variable velocity or non-zero acceleration: Not like the uniform acceleration, the body is said to have a non-uniform motion when the velocity of a body changes by unequal amounts in equal intervals of time. The rate of change of its velocity changes at different points of time during its movement.