Question:
The displacement of a particle executing simple harmonic motion is given by \(y=A_0+A sin\omega t+Bcos\omega t.\) Then the amplitude of its oscillation is given by:
The displacement of a particle executing simple harmonic motion is given by \(y=A_0+A sin\omega t+Bcos\omega t.\) Then the amplitude of its oscillation is given by:
Updated On: Apr 14, 2025
- \(A_0+\sqrt {A^2+B^2}\)
- \(\sqrt {A^2+B^2}\)
- \(\sqrt {A_0^2+(A^2+B^2})\)
- \(A+B\)
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The Correct Option is B
Solution and Explanation
The correct option is (B) :\(\sqrt {A^2+B^2}\)
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