Question:
The disintegration rate of a certain radioactive sample at any instant is $4250$ disintegrations per minute $10$ minutes later, the rate becomes $2250 $ disintegrations per minute The approximate decay constant is : (Take $\log _{10} 188=0274$ )
The disintegration rate of a certain radioactive sample at any instant is $4250$ disintegrations per minute $10$ minutes later, the rate becomes $2250 $ disintegrations per minute The approximate decay constant is : (Take $\log _{10} 188=0274$ )
Updated On: Mar 19, 2025
- \(0.02 \,\min ^{-1}\)
- \(2.7 \,\min ^{-1}\)
- \(0.063 \,\min ^{-1}\)
- \(6.3 \,\min ^{-1}\)
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The Correct Option is C
Solution and Explanation
The correct option is(C): 0.063 min−1.
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