Question:
The disc of a siren containing $60$ holes rotates at a constant speed of $360\, rpm$. The emitted sound is in unison with a tuning fork of frequency :
The disc of a siren containing $60$ holes rotates at a constant speed of $360\, rpm$. The emitted sound is in unison with a tuning fork of frequency :
Updated On: Jan 30, 2025
- 10 Hz
- 360 Hz
- 216 Hz
- 60 Hz
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Number of holes in the disk determines the number of waves produced on each rotation $= 60$
The total number of waves per second determines the frequency of the sound.
So frequency $=60 \times \frac{360}{60}=360 \,Hz$
The total number of waves per second determines the frequency of the sound.
So frequency $=60 \times \frac{360}{60}=360 \,Hz$
Was this answer helpful?
0
0
Top Questions on sound
- The fundamental frequency of a closed organ pipe of length \( 20 \, \mathrm{cm} \) is equal to the second overtone of an organ pipe open at both ends. What is the length of the organ pipe open at both ends?
- A point source is placed at origin. Its intensity at distance of 2 cm from source is I then intensity at distance 4 cm from the source shall be.
- The ratio of the speed of sound in hydrogen gas to the speed of sound in oxygen gas at the same temperature is:
- Which of the following is a transducer ?
(A) Loudspeaker
(B) Amplifier
(C) Rectifier
(D) Microphone
Choose the correct answer from the options given below : - An organ pipe 40cm long is open at both ends. The speed of sound in air is 360ms-1 . The frequency of the second harmonic is ____Hz.
View More Questions
Questions Asked in BITSAT exam
- Let \( ABC \) be a triangle and \( \vec{a}, \vec{b}, \vec{c} \) be the position vectors of \( A, B, C \) respectively. Let \( D \) divide \( BC \) in the ratio \( 3:1 \) internally and \( E \) divide \( AD \) in the ratio \( 4:1 \) internally. Let \( BE \) meet \( AC \) in \( F \). If \( E \) divides \( BF \) in the ratio \( 3:2 \) internally then the position vector of \( F \) is:
- BITSAT - 2024
- Vectors
- Let \( \mathbf{a} = \hat{i} - \hat{k}, \mathbf{b} = x\hat{i} + \hat{j} + (1 - x)\hat{k}, \mathbf{c} = y\hat{i} + x\hat{j} + (1 + x - y)\hat{k} \). Then, \( [\mathbf{a} \, \mathbf{b} \, \mathbf{c}] \) depends on:}
- BITSAT - 2024
- Vectors
- Let the foot of perpendicular from a point \( P(1,2,-1) \) to the straight line \( L : \frac{x}{1} = \frac{y}{0} = \frac{z}{-1} \) be \( N \). Let a line be drawn from \( P \) parallel to the plane \( x + y + 2z = 0 \) which meets \( L \) at point \( Q \). If \( \alpha \) is the acute angle between the lines \( PN \) and \( PQ \), then \( \cos \alpha \) is equal to:
- The magnitude of projection of the line joining \( (3,4,5) \) and \( (4,6,3) \) on the line joining \( (-1,2,4) \) and \( (1,0,5) \) is:
- BITSAT - 2024
- Vectors
- The angle between the lines whose direction cosines are given by the equations \( 3l + m + 5n = 0 \) and \( 6m - 2n + 5l = 0 \) is:
- BITSAT - 2024
- Vectors
View More Questions