Step 1: The Chezy’s equation for velocity \( V \) in an open channel is: \[ V = C \sqrt{RS} \] where: - \( R \) is the hydraulic radius (\( L \)), - \( S \) is the slope (dimensionless), - \( C \) is Chezy’s coefficient.
Step 2: Solving for \( C \): \[ C = V \div \sqrt{R} \] Using \( V = LT^{-1} \) and \( R = L \), we get: \[ C = \frac{LT^{-1}}{L^{1/2}} = L^{1/2} T^{-1} \] Thus, the correct answer is (D) \( L^{1/2} T^{-1} \).
Consider the following statements:
A. Surface tension arises due to extra energy of the molecules at the interior as compared to the molecules at the surface of a liquid.
B. As the temperature of liquid rises, the coefficient of viscosity increases.
C. As the temperature of gas increases, the coefficient of viscosity increases.
D. The onset of turbulence is determined by Reynolds number.
E. In a steady flow, two streamlines never intersect.
Choose the correct answer from the options given below:
$\text{The fractional compression } \left( \frac{\Delta V}{V} \right) \text{ of water at the depth of } 2.5 \, \text{km below the sea level is } \_\_\_\_\_\_\_\_\_\_ \%. \text{ Given, the Bulk modulus of water } = 2 \times 10^9 \, \text{N m}^{-2}, \text{ density of water } = 10^3 \, \text{kg m}^{-3}, \text{ acceleration due to gravity } g = 10 \, \text{m s}^{-2}.$
A closed-loop system has the characteristic equation given by: $ s^3 + k s^2 + (k+2) s + 3 = 0 $.
For the system to be stable, the value of $ k $ is: