Question:

The dimensions of a cone are measured using a scale with a least count of 2 mm. The diameter of the base and the height are both measured to be 20.0 cm. The maximum percentage error in thedetermination of the volume is ______.

Updated On: Mar 8, 2025
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Correct Answer: 3

Solution and Explanation

Volume of a Cone and Error Calculation 

The volume of a cone is given by:

\[ V = \frac{1}{3} \pi R^2 H \] where \( R \) is the radius of the base and \( H \) is the height of the cone.

Step 1: Expression for Relative Error in Volume

The relative error in the volume \( V \) is: \[ \frac{\Delta V}{V} = 2 \frac{\Delta R}{R} + \frac{\Delta H}{H} \]

Step 2: Calculate the Percentage Error in Volume

The percentage error in measuring the volume is: \[ \% \text{error in volume} = 2 \cdot \frac{\Delta R}{R} + \frac{\Delta H}{H} \cdot 100 \] Substitute \( \Delta R = 0.2 \, \text{cm} \), \( R = 20 \, \text{cm} \), \( \Delta H = 0.2 \, \text{cm} \), and \( H = 20 \, \text{cm} \): \[ \% \text{error in volume} = 2 \cdot \frac{0.2}{20} + \frac{0.2}{20} \cdot 100 \] Simplify: \[ \% \text{error in volume} = \left[ 2 \cdot 0.01 + 0.01 \right] \cdot 100 = 3 \]

Final Answer:

The maximum percentage error in the determination of the volume is:

\[ \boxed{3\%} \]

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