\( [L^{-1}M^1T^{-2}] \)
\( [L^2M^1T^{-2}] \)
\( [L^1M^1T^{-1}] \)
Step 1: Surface tension is defined as the force per unit length: \[ T = \frac{{Force}}{{Length}}. \] The dimensional formula of force is: \[ [F] = M L T^{-2}. \] By dividing force by length (\( L \)), we obtain the dimensional formula for surface tension: \[ [T] = M L^{-1} T^{-2}. \] Step 2: After comparing with the given options, the correct answer is option (d).
While determining the coefficient of viscosity of the given liquid, a spherical steel ball sinks by a distance \( x = 0.8 \, \text{m} \). The radius of the ball is \( 2.5 \times 10^{-3} \, \text{m} \). The time taken by the ball to sink in three trials are tabulated as shown:
The expression given below shows the variation of velocity \( v \) with time \( t \): \[ v = \frac{At^2 + Bt}{C + t} \] The dimension of \( A \), \( B \), and \( C \) is:
The slope of the tangent to the curve \( x = \sin\theta \) and \( y = \cos 2\theta \) at \( \theta = \frac{\pi}{6} \) is ___________.
Solve the following L.P.P. by graphical method:
Maximize:
\[ z = 10x + 25y. \] Subject to: \[ 0 \leq x \leq 3, \quad 0 \leq y \leq 3, \quad x + y \leq 5. \]