\( [L^{-1}M^1T^{-2}] \)
\( [L^2M^1T^{-2}] \)
\( [L^1M^1T^{-1}] \)
Step 1: Surface tension is defined as the force per unit length: \[ T = \frac{{Force}}{{Length}}. \] The dimensional formula of force is: \[ [F] = M L T^{-2}. \] By dividing force by length (\( L \)), we obtain the dimensional formula for surface tension: \[ [T] = M L^{-1} T^{-2}. \] Step 2: After comparing with the given options, the correct answer is option (d).
A quantity \( X \) is given by: \[ X = \frac{\epsilon_0 L \Delta V}{\Delta t} \] where:
- \( \epsilon_0 \) is the permittivity of free space,
- \( L \) is the length,
- \( \Delta V \) is the potential difference,
- \( \Delta t \) is the time interval.
The dimension of \( X \) is the same as that of:
The expression given below shows the variation of velocity \( v \) with time \( t \): \[ v = \frac{At^2 + Bt}{C + t} \] The dimension of \( A \), \( B \), and \( C \) is:
Match List-I with List-II.
Choose the correct answer from the options given below :