To determine the difference between the greatest and smallest of the given fractions, we need to compare each of them. The fractions are $\frac{1}{2}$, $\frac{8}{11}$, $\frac{7}{8}$, $\frac{7}{9}$, and $\frac{5}{6}$. To make comparison easy, convert each fraction to a common denominator or compare them in decimal form.
Converting each fraction to decimal:
By comparing these decimal values, we can identify the smallest and greatest fractions:
Next, calculate the difference between the greatest and smallest fractions:
Difference = $\frac{7}{8} - \frac{1}{2}$
To subtract, use a common denominator (8):
$\frac{1}{2} = \frac{4}{8}$
So, $\frac{7}{8} - \frac{4}{8} = \frac{3}{8}$
Therefore, the difference between the greatest and smallest fractions is $\frac{3}{8}$.
Finding the Difference Between Fractions
\(\frac{1}{2}, \frac{8}{11}, \frac{7}{8}, \frac{7}{9}, \frac{5}{6}\).
Let's approximate these fractions as decimals to compare them:
From these approximations, we can see that the greatest fraction is \(\frac{7}{8}\) and the smallest fraction is \(\frac{1}{2}\).
Now, let's find the difference: \(\frac{7}{8} - \frac{1}{2}\).
To subtract, we need a common denominator, which is 8.
\(\frac{7}{8} - \frac{1}{2} = \frac{7}{8} - \frac{4}{8} = \frac{7-4}{8} = \frac{3}{8}\)
Therefore, the difference between the greatest and smallest fractions is \(\frac{3}{8}\).
Directions: In Question Numbers 19 and 20, a statement of Assertion (A) is followed by a statement of Reason (R).
Choose the correct option from the following:
(A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
(B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
(C) Assertion (A) is true, but Reason (R) is false.
(D) Assertion (A) is false, but Reason (R) is true.
Assertion (A): For any two prime numbers $p$ and $q$, their HCF is 1 and LCM is $p + q$.
Reason (R): For any two natural numbers, HCF × LCM = product of numbers.