To determine the difference between the greatest and smallest of the given fractions, we need to compare each of them. The fractions are $\frac{1}{2}$, $\frac{8}{11}$, $\frac{7}{8}$, $\frac{7}{9}$, and $\frac{5}{6}$. To make comparison easy, convert each fraction to a common denominator or compare them in decimal form.
Converting each fraction to decimal:
By comparing these decimal values, we can identify the smallest and greatest fractions:
Next, calculate the difference between the greatest and smallest fractions:
Difference = $\frac{7}{8} - \frac{1}{2}$
To subtract, use a common denominator (8):
$\frac{1}{2} = \frac{4}{8}$
So, $\frac{7}{8} - \frac{4}{8} = \frac{3}{8}$
Therefore, the difference between the greatest and smallest fractions is $\frac{3}{8}$.
Finding the Difference Between Fractions
\(\frac{1}{2}, \frac{8}{11}, \frac{7}{8}, \frac{7}{9}, \frac{5}{6}\).
Let's approximate these fractions as decimals to compare them:
From these approximations, we can see that the greatest fraction is \(\frac{7}{8}\) and the smallest fraction is \(\frac{1}{2}\).
Now, let's find the difference: \(\frac{7}{8} - \frac{1}{2}\).
To subtract, we need a common denominator, which is 8.
\(\frac{7}{8} - \frac{1}{2} = \frac{7}{8} - \frac{4}{8} = \frac{7-4}{8} = \frac{3}{8}\)
Therefore, the difference between the greatest and smallest fractions is \(\frac{3}{8}\).
The largest $ n \in \mathbb{N} $ such that $ 3^n $ divides 50! is:
The following data shows the number of students in different streams in a school:
Which type of graph is best suited to represent this data?
What comes next in the series?
\(2, 6, 12, 20, 30, \ ?\)