Let the radius of the earth be R and the radius of the moon be r
Diameter of the moon = \(\frac{1}{4}\) × diameter of the earth
The radius of the moon = \(\frac{1}{4}\) × radius of the earth
r = \(\frac{1}{4}\) × R
r = \(\frac{R}{4}\)
The volume of the earth = \(\frac{4}{3}\pi\) R3
The volume of the moon = \(\frac{4}{3}\pi\) r3
= \(\frac{4}{3}\pi\) \((\frac{R}{4})^3\)
= \(\frac{1}{64} ×\frac{ 4}{3}\)\(\pi\) R3
\(⇒\) The volume of the moon = \(\frac{1}{64}\)× Volume of the earth
Therefore, the volume of the moon is \(\frac{1}{64}\) times the volume of the earth.
Express the following linear equations in the form ax + by + c = 0 and indicate the values of a, b and c in each case:
(i) 2x + 3y = 9.35
(ii) x – \(\frac{y}{5}\)– 10 = 0
(iii) –2x + 3y = 6
(iv) x = 3y
(v) 2x = –5y
(vi) 3x + 2 = 0
(vii) y – 2 = 0
Which one of the following options is true, and why? y = 3x + 5 has
(i) a unique solution,
(ii) only two solutions,
(iii) infinitely many solutions