Let the radius of the earth be R and the radius of the moon be r
Diameter of the moon = \(\frac{1}{4}\) × diameter of the earth
The radius of the moon = \(\frac{1}{4}\) × radius of the earth
r = \(\frac{1}{4}\) × R
r = \(\frac{R}{4}\)
The volume of the earth = \(\frac{4}{3}\pi\) R3
The volume of the moon = \(\frac{4}{3}\pi\) r3
= \(\frac{4}{3}\pi\) \((\frac{R}{4})^3\)
= \(\frac{1}{64} ×\frac{ 4}{3}\)\(\pi\) R3
\(⇒\) The volume of the moon = \(\frac{1}{64}\)× Volume of the earth
Therefore, the volume of the moon is \(\frac{1}{64}\) times the volume of the earth.
List-I | List-II | ||
(A) | Volume of cone | (I) | \(\frac{1}{3}\pi h(r_1^2+r_2^2+r_1r_2)\) |
(B) | Volume of sphere | (II) | \(\frac{1}{3}\pi r^2h\) |
(C) | Volume of Frustum | (III) | \(\pi r^2h\) |
(D) | Volume of cylinder | (IV) | \(\frac{4}{3}\pi r^3\) |
In Fig. 9.26, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠ BEC = 130° and ∠ ECD = 20°. Find ∠ BAC.