Question:

The density of ice is $9.2 \times 10^2 \, \text{kg/m}^3$. If a chunk displaces $10^{-2} \, \text{m}^3$, the buoyant force on the ice is most nearly:

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Remember that the buoyant force is proportional to the density of the fluid, the volume displaced, and the gravitational acceleration.
Updated On: Mar 30, 2025
  • 0.1 N
  • 10 N
  • 100 N
  • 1000 N
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The Correct Option is C

Solution and Explanation


The buoyant force is given by the formula: \[ F_b = \rho \cdot V \cdot g \] where: $\rho = 9.2 \times 10^2 \, \text{kg/m}^3$ (density of ice), $V = 10^{-2} \, \text{m}^3$ (volume displaced), $g = 9.8 \, \text{m/s}^2$ (acceleration due to gravity). Substituting the values: \[ F_b = (9.2 \times 10^2) \cdot (10^{-2}) \cdot (9.8) \approx 100 \, \text{N} \]
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