The density of a material in $CGS$ system of units is $4\,g\,cm^3$. In a system of units in which unit of length is $10\,cm$ and unit of mass is $100\,g$. the value of density of material will be
- $0.04$
- $0.4$
- $40$
- $400$
The Correct Option is C
Solution and Explanation
$\Rightarrow d =\frac{ M }{ L ^{3}}$
$\Rightarrow d =\frac{4 \,gm }{ cm ^{3}}=\frac{4(1 / 100)}{10^{-3}} $
$=40 \frac{ gm }{ cm ^{3}}$
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Concepts Used:
Uncertainty in Measurement
- Atoms and molecules consist of very low mass. But they are present in huge numbers.
- Chemists have to deal with numbers as large as 602,200,000,000,000,000,000,000, which is the number of molecules of 2g of hydrogen.
- There are even other constants like the speed of light, charges on particles, Avogadro’s number and etc.
- To handle these large or small numbers, we use the following notation: m × 10n, which is, m times ten raised to the power of n. In this expression, n is an exponent having positive and negative values and m is that number that varies from 1.000… and 9.999…
- The scientific notation 573.672 can be written as 5.73672 × 102 and in the same way, 0.000089 can also be written as 8.9 × 10-5.
- All of these help us to attain easier handling, better precision, and accuracy while performing operations on numbers with high magnitudes.
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