Question:
The density of $3M$ solution of sodium chloride is $1.252\, g\, mL^{-1}$. The molality of the solution will be:
(molar mass, $NaCl = 585\, g\, mol^{-1}$)
The density of $3M$ solution of sodium chloride is $1.252\, g\, mL^{-1}$. The molality of the solution will be:
(molar mass, $NaCl = 585\, g\, mol^{-1}$)
Updated On: Jul 2, 2024
- 260 m
- 2.18 m
- 2.79 m
- 3.00 m
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The Correct Option is C
Solution and Explanation
The relation between molarity (M) and molality (m) is
$d=M\left(\frac{1}{m}+\frac{M_{2}}{1000}\right), M_{2}=$ Mol. mass of solute
On putting value
$1.252=3\left(\frac{1}{m}+\frac{58.5}{1000}\right)$
on solving $m = 2.79$
$d=M\left(\frac{1}{m}+\frac{M_{2}}{1000}\right), M_{2}=$ Mol. mass of solute
On putting value
$1.252=3\left(\frac{1}{m}+\frac{58.5}{1000}\right)$
on solving $m = 2.79$
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