Question:

The degrees of the differential equations $\frac{dy}{dx}+y^{2} = x$ and $\frac{d^{2}y}{dx^{2}} + y = sin\,x$ are equal. The degree of a differential equation, when it is a polynomial equation in derivatives, is the highest positive integral power of the highest order derivative involved in the differential equation, otherwise degree is not defined.

Updated On: Jul 28, 2022
  • Statement 1 is true, Statement 2 is true. Statement 2 is not a correct explanation of Statement 1.
  • Statement 1 is felse, Statement 2 is true.
  • Statement 1 is true, Statement 2 is false.
  • Statement 1 is true, Statement 2 is true; Statement 2 is a correct explanation of Statement 1.
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

Given differential equations are $\frac{dy}{dx}+y^{2} = x$ and $\frac{d^{2}y}{dx^{2}} + y = sin\,x $ Their degrees are 1. Both have equal degree. Also, Statement - 2 is the correct explanation for Statement -1.
Was this answer helpful?
0
0

Concepts Used:

Order and Degree of Differential Equation

The equation that helps us to identify the type and complexity of the differential equation is the order and degree of a differential equation.

The Order of a Differential Equation:

The highest order of the derivative that appears in the differential equation is the order of a differential equation.

The Degree of a Differential Equation:

The highest power of the highest order derivative that appears in a differential equation is the degree of a differential equation. Its degree is always a positive integer.

For examples:

  • 7(d4y/dx4)3 + 5(d2y/dx2)4+ 9(dy/dx)8 + 11 = 0 (Degree - 3)
  • (dy/dx)2 + (dy/dx) - Cos3x = 0 (Degree - 2)
  • (d2y/dx2) + x(dy/dx)3 = 0 (Degree - 1)