The given differential equation is \(\left( \frac{d^2 y}{dx^2} \right)^{\frac{4}{5}} = 10 \frac{dy}{dx} + 2\). To determine the degree and order, we follow these steps:
To express the equation in a polynomial form, eliminate the fractional power by raising both sides to the power of 5:
\(\left( \left( \frac{d^2 y}{dx^2} \right)^{\frac{4}{5}} \right)^5 = (10 \frac{dy}{dx} + 2)^5\).
This results in:
\(\left( \frac{d^2 y}{dx^2} \right)^4 = (10 \frac{dy}{dx} + 2)^5\).
Now, the degree of the differential equation is the highest power of \(\frac{d^2 y}{dx^2}\), which is 4.
Therefore, the degree is 4 and the order is 2.
| Attribute | Value |
|---|---|
| Degree | 4 |
| Order | 2 |
The correct answer is: Degree 4, Order 2.
Let \( f : [1, \infty) \to [2, \infty) \) be a differentiable function. If
\( 10 \int_{1}^{x} f(t) \, dt = 5x f(x) - x^5 - 9 \) for all \( x \ge 1 \), then the value of \( f(3) \) is ______.