Riboflavin, milk
Riboflavin, fish
Pyridoxine, curd
Pyridoxine, cereals
Step 1: Identify Vitamin (X) that causes convulsions due to deficiency.
Convulsions are neurological symptoms that can be caused by the deficiency of certain vitamins. Among the options provided, Pyridoxine deficiency is well-known to cause neurological issues, including convulsions. Riboflavin (Vitamin B2): Deficiency of riboflavin causes ariboflavinosis, symptoms of which include cracks and sores at the corners of the mouth (cheilosis), inflammation of the tongue (glossitis), and skin disorders. It is not primarily associated with convulsions.
Pyridoxine (Vitamin B6): Deficiency of pyridoxine can lead to neurological symptoms such as seizures or convulsions, especially in infants. It is crucial for the synthesis of neurotransmitters. Therefore, Vitamin (X) is Pyridoxine.
Step 2: Identify a common source (Y) of Vitamin X (Pyridoxine).
Now that X is identified as Pyridoxine, we need to find its source (Y) from the options.
Milk: While milk contains some B vitamins, it is not a primary or most significant source of pyridoxine.
Fish: Fish is a good source of several vitamins, including some B vitamins, but it is not the most commonly cited broad source associated with this question's options.
Curd: Curd (yogurt) contains B vitamins, but again, it's not the primary or most impactful source for pyridoxine in the context of the options.
Cereals: Whole grain cereals, fortified cereals, and many types of grains are excellent sources of Pyridoxine (Vitamin B6).
Therefore, a significant source (Y) of Pyridoxine (X) is cereals.
Step 3: Combine X and Y to find the correct option.
Based on the analysis, X is Pyridoxine and Y is cereals. |
This matches option 4.
Why can't vitamin C be stored in our body?
If \( \vec{u}, \vec{v}, \vec{w} \) are non-coplanar vectors and \( p, q \) are real numbers, then the equality:
\[ [3\vec{u} \quad p\vec{v} \quad p\vec{w}] - [p\vec{v} \quad \vec{w} \quad q\vec{u}] - [2\vec{w} \quad q\vec{v} \quad q\vec{u}] = 0 \]
holds for:
Statement-I: In the interval \( [0, 2\pi] \), the number of common solutions of the equations
\[ 2\sin^2\theta - \cos 2\theta = 0 \]
and
\[ 2\cos^2\theta - 3\sin\theta = 0 \]
is two.
Statement-II: The number of solutions of
\[ 2\cos^2\theta - 3\sin\theta = 0 \]
in \( [0, \pi] \) is two.
If \( A \) and \( B \) are acute angles satisfying
\[ 3\cos^2 A + 2\cos^2 B = 4 \]
and
\[ \frac{3 \sin A}{\sin B} = \frac{2 \cos B}{\cos A}, \]
Then \( A + 2B = \ ? \)