The DC current gain (\( \beta \)) of a BJT is 50. Assuming that the emitter injection efficiency is 0.995, the base transport factor is
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For calculating the base transport factor, remember that it is related to current gain and emitter injection efficiency through the equation \( \beta = \gamma \times \beta_T \).
The DC current gain \( \beta \) of a BJT is related to the emitter injection efficiency \( \gamma \) and the base transport factor \( \beta_T \) by the equation:
\[
\beta = \gamma \times \beta_T
\]
Given \( \beta = 50 \) and \( \gamma = 0.995 \), solving for \( \beta_T \):
\[
\beta_T = \frac{\beta}{\gamma} = \frac{50}{0.995} = 0.985
\]
Thus, the base transport factor is 0.985. Therefore, the correct answer is option (1).
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