The DC current gain \( \beta \) of a BJT is related to the emitter injection efficiency \( \gamma \) and the base transport factor \( \beta_T \) by the equation:
\[
\beta = \gamma \times \beta_T
\]
Given \( \beta = 50 \) and \( \gamma = 0.995 \), solving for \( \beta_T \):
\[
\beta_T = \frac{\beta}{\gamma} = \frac{50}{0.995} = 0.985
\]
Thus, the base transport factor is 0.985. Therefore, the correct answer is option (1).