The correct truth table for the following logic circuit is :
The Correct Option is B
Solution and Explanation
The circuit consists of an AND gate, a NOT gate, and an OR gate. The output \(Y\) is determined as follows:
- The output of the AND gate is \(A \cdot B\).
- The output of the NOT gate is \(\overline{A \cdot B}\).
- The output \(Y\) is the OR of \(\overline{A \cdot B}\) and \(B\):
\[ Y = \overline{A \cdot B} + B \]
Step-by-Step Evaluation of Truth Table:
| A | B | A · B | &overline;A · B | Y = &overline;A · B + B |
|---|---|---|---|---|
| 0 | 0 | 0 | 1 | 1 |
| 0 | 1 | 0 | 1 | 1 |
| 1 | 0 | 0 | 1 | 1 |
| 1 | 1 | 1 | 0 | 1 |
Thus, the correct truth table is represented in Option (2).
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