The correct statements about the adsorption of gas on solid adsorbent are:
Adsorption is always exothermic. Physisorption may transform into chemisorption at high temperature. Physisorption increases with increasing temperature but chemisorption decreases with increasing temperature. In physisorption enthalpy of adsorption is 100 kJ mol\(^{-1}\).
II & IV only
III & IV only
II & III only
I & II only
Adsorption is a process where gas molecules adhere to a solid surface. This process releases energy, making it exothermic.
Statement I is correct.
Physisorption involves weak van der Waals forces. At high temperatures, these forces can be overcome, and chemical bonds may form, leading to chemisorption.
Statement II is correct.
Physisorption decreases with increasing temperature because the kinetic energy of the gas molecules increases, making it harder for them to adhere to the surface.
Chemisorption also decreases with increasing temperature after reaching an optimum temperature, as the activation energy required for bond formation is supplied.
Statement III is incorrect.
The enthalpy of adsorption for physisorption is typically in the range of 20-40 kJ mol\(^{-1}\), not 100 kJ mol\(^{-1}\).
Statement IV is incorrect.
Therefore, the correct statements are I and II.
Final Answer:Observe the following reactions:
\( AB(g) + 25 H_2O(l) \rightarrow AB(H_2S{O_4}) \quad \Delta H = x \, {kJ/mol}^{-1} \)
\( AB(g) + 50 H_2O(l) \rightarrow AB(H_2SO_4) \quad \Delta H = y \, {kJ/mol}^{-1} \)
The enthalpy of dilution, \( \Delta H_{dil} \) in kJ/mol\(^{-1}\), is:
Identify the sets of species having the same bond order:
(i) \( {F}_2, {O}_2^{2-} \)
(ii) CO, NO\(^{+}\)
(iii) \(N_2\), \(O_2\)
(iv) \(H_2\), \(B_2\)
The correct option is: