Question

The correct increasing order of bond order values for the concerned species is

• A. \( \left(O_{2}\right)^{-}\)
• B. \(\left(O_{2}\right)^{-}\)
• C. \( \left(O_{2}\right)\)
• D. \(\left(O_{2}\right)\)

Answer 1

The Correct Option is A

\(O_2^-: KKσ2s^2σ^*2s^2σ2p_z\pi^22p_y^2\)
\(\pi^{*}2P^{2}_{x}=\pi^{*}2p^{1}_{y}\) 
Bond order \(=\frac{1}{2}(8-5)=\frac{3}{2}=1.5\)
\(O_{2}: KK {\sigma}2S^{2}{\sigma}^{*}2s^{2}{\sigma}2p_{z} ^{2}\pi2p^{2}_{x}\)
\(=\pi2p_{y} ^{2}\pi ^{*}2P^{1}_{x}=\pi^{*}2p^{1}_{y}\) 
Bond order \(=\frac{1}{2}(8-4)=2\)
\(N_{2}: KK{\sigma}2S^{2}{\sigma} ^{*}2s^{2}\pi 2p^{2}_{x}\)
\(=\pi 2p^{2}_{y} {\sigma}2p^{2}_{z}\) 
Bond order \(=\frac{1}{2}(8-2)=3\)
\(N^{+}_{2} : KK{\sigma}2s^{2}{\sigma} ^{*}2 s^{2}\pi2p^{2}_{x}\)
\(=\pi 2p^{2}_{y} {\sigma}2p^{1}_{z}\) 
Bond order \(=\frac{1}{2}(7-2)\)
\(=\frac{5}{2}=2.5\) 
Hence, the increasing order of bond order values is : 
\(O^{-}_{2}\)