$[{Rn}] 5f^6 6d^1 7s^0$
Step 1: Uranium (Z=92) belongs to the actinide series, and its electron configuration follows the Aufbau principle.
Step 2: The electron configuration of uranium is: \[ [{Rn}] 5f^3 6d^1 7s^2 \] where: - Rn represents the radon core ($Z=86$). - The remaining six electrons occupy the $5f$, $6d$, and $7s$ orbitals.
Step 3: The actinide elements tend to have electrons in both $f$ and $d$ orbitals due to energy level mixing.
Step 4: Therefore, the correct answer is (A). \bigskip
List-I Tetrahedral Complex | List-II Electronic configuration |
---|---|
(A) TiCl4 | (I) e2, t20 |
(B) [FeO4]2- | (II) e4, t23 |
(C) [FeCl4]- | (III) e0, t22 |
(D) [CoCl4]2- | (IV) e2, t23 |
The values of X, Y, and Z in the following chemical equation are respectively:
\( S_8 + X HNO_3 ({conc.}) \rightarrow Y H_2SO_4 + X NO_2 + Z H_2O \)
Iron does not exhibit ___________ oxidation state.