$[{Rn}] 5f^6 6d^1 7s^0$
Step 1: Uranium (Z=92) belongs to the actinide series, and its electron configuration follows the Aufbau principle.
Step 2: The electron configuration of uranium is: \[ [{Rn}] 5f^3 6d^1 7s^2 \] where: - Rn represents the radon core ($Z=86$). - The remaining six electrons occupy the $5f$, $6d$, and $7s$ orbitals.
Step 3: The actinide elements tend to have electrons in both $f$ and $d$ orbitals due to energy level mixing.
Step 4: Therefore, the correct answer is (A). \bigskip
Let \( I = \int_{-\frac{\pi}{4}}^{\frac{\pi}{4}} \frac{\tan^2 x}{1+5^x} \, dx \). Then: