Question:

The corner points of the feasible region of an LPP are (0,2), (3,0), (6,0), (6,8) and (0,5), then the minimum value of z = 4x + 6y occurs at

Updated On: Apr 20, 2024
  • finite number of points
  • only one point
  • infinite number of points
  • only two points
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The Correct Option is D

Solution and Explanation

z=4x+6yz = 4x + 6y
Let's substitute the coordinates of each corner point into the objective function:
For point (0,2):z=4(0)+6(2)=12(0, 2): z = 4(0) + 6(2) = 12
 For point (3,0):z=4(3)+6(0)=12(3, 0): z = 4(3) + 6(0) = 12
For point (6,0):z=4(6)+6(0)=24(6, 0): z = 4(6) + 6(0) = 24
For point (6,8):z=4(6)+6(8)=72(6, 8): z = 4(6) + 6(8) = 72
For point (0,5):z=4(0)+6(5)=30(0, 5): z = 4(0) + 6(5) = 30
From the evaluations, we can see that the minimum value of z occurs at two points, namely (0, 2) and (3, 0), both having a value of 12. 
Therefore, the correct option is (D) only two points.

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