In SN1 reactions, the rate-determining step is the departure of the leaving group. In the case of aromatic compounds, a resonance-stabilized carbocation can form if the leaving group is attached to the ring, which makes the reaction faster. Hence, the phenyl bromide (C6H5Br) undergoes the reaction most rapidly.
0.1 mole of compound S will weigh ....... g,
(given the molar mass in g mol\(^{-1}\) \( {C} = 12, \, {H} = 1, \, {O} = 16 )\):
If \( {A}_2{B} \) is 30% ionised in an aqueous solution, then the value of van't Hoff factor \( i \) is:
Match List - I with List - II:
Choose the correct answer from the options given below: