Question:

The complementary function of the differential equation \( y'' + 16y = x \sin px, \, p = 4, \) is given by:

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For constant-coefficient differential equations, use the characteristic equation to find the complementary function.
Updated On: Dec 28, 2024
  • \( A \cos(16x) + B \sin(16x), \) where \( A \) and \( B \) are constants.
  • \( A \cos(4x) + B \sin(4x), \) where \( A \) and \( B \) are constants.
  • \( A \cos(8x) + B \sin(8x), \) where \( A \) and \( B \) are constants.
  • \( A \cos(2x) + B \sin(2x), \) where \( A \) and \( B \) are constants.
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The Correct Option is B

Solution and Explanation

The complementary function solves the homogeneous equation \( y'' + 16y = 0 \). Here, the characteristic equation is \( r^2 + 16 = 0 \), giving roots \( \pm 4i \). The solution is:
\( y_c = A \cos(4x) + B \sin(4x). \)

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