Question:

The combustion of glucose takes place according to the equation:\[\text{C}_6\text{H}_{12}\text{O}_6 + 6\text{O}_2 \rightarrow 6\text{CO}_2 + 6\text{H}_2\text{O}, \Delta H = -72 \text{ k-cal}\]The energy required for the combustion of 1.6 g of glucose is

Updated On: Jun 21, 2024
  • 0.064 k-cal
  • 0.64 k-cal
  • 6.4 k-cal
  • 64 k-cal
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The Correct Option is B

Solution and Explanation

The correct option is (B):0.64 k-cal
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