Question:

The co-ordinates of a moving particle at any time $'t'$ are given by $x = \alpha t^3$ and $y = \beta t^3$. The speed to the particle at time $'t'$ is given by

Updated On: Jul 2, 2022
  • $3t\sqrt{\alpha^{2}+\beta^{2}}$
  • $3t^2\sqrt{\alpha^{2}+\beta^{2}}$
  • $t^2\sqrt{\alpha^{2}+\beta^{2}}$
  • $\sqrt{\alpha^{2}+\beta^{2}}$
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The Correct Option is B

Solution and Explanation

Speed $=\left|\vec{v}\right|=\sqrt{\left(3\alpha t^{2}\right)^{2}+\left(3\beta t^{2}\right)^{2}}=3t^{2}\sqrt{\alpha^{2}+\beta^{2}}.$
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration