Question

The circle $x^2+y^2+4x-7y+12=0$ cuts an intercept on $y$ -axis of length

Answer 1

Correct Answer: 1

Explanation:
Given:Equation of a circle, $x^2+y^2+4x-7y+12=0$We have to find the $y$ -intercept made by the circle.Intercept on $y$ -axis made by a circle $x^2+y^2+2gx+2fy+c=0$ is $2\sqrt{(f^2-c)}$We have equation of the given circle, $x^2+y^2+4x-7y+12=0$Thus required intercept$=2\sqrt{{\left(\frac{-7}{2}\right)}^2-12}$$=2\sqrt{(\frac{49}{4}-12)}$$=1$Hence, the answer is 1.00.