The charge required for the reduction of 1 mol of \( MnO_4^- \) to \( MnO_2 \) is
Show Hint
- 1 F
- 3 F
- 5 F
- 6 F
The Correct Option is C
Solution and Explanation
Step 1: In the reduction of \( MnO_4^- \) to \( MnO_2 \), the manganese ion undergoes a change in oxidation state from +7 to +4, which requires 5 moles of electrons. Hence, the charge required is 5 F (Faradays).
Step 2: Thus, the correct answer is option (3).
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