Question:

The Brewsters angle $i_b$ for an interface should be:

Updated On: Jun 5, 2024
  • \(0< i b < 30\)

  • \(30< i_b < 45\)

  • \(45< i_b < 90\)

  • \(i_b = 90\)

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The Correct Option is C

Solution and Explanation

Brewster's angle is the angle at which light with a specific polarization passes through a dielectric surface without any reflection. When unpolarized light hits the surface at this angle, the reflected light is completely polarized.

Calculation:

At the interface, Brewster's angle \(i_b\)​ is given by: \(μ=tan⁡i_b  \ (1)\)

Here, \(\mu\) is the refractive index of the material, which ranges from 1 to ∞: \(1 < \mu < \infty\)

Substituting equation (1) into this range, we get: \(1 < \tan i_b < \infty\)

Therefore, the polarization angle \( i_b\) falls within: \(\tan^{-1}(1) < i_b < \tan^{-1}(\infty)\)
\(\Rightarrow 45^\circ < i_b < 90^\circ\)

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