The bond order of which of the following two species is the same?
Show Hint
- \( O_2, N_2 \)
- \( C_2, O_2 \)
- \( B_2, C_2 \)
- \( F_2, C_2 \)
The Correct Option is B
Solution and Explanation
Step 1: Use the Bond Order Formula Bond order is given by: \[ \text{Bond order} = \frac{\text{Number of bonding electrons} - \text{Number of antibonding electrons}}{2} \]
Step 2: Compute Bond Orders \( C_2 \): Electronic configuration in molecular orbitals gives bond order = 2. \( O_2 \): Electronic configuration in molecular orbitals also gives bond order = 2. Since both species have the same bond order, they are the correct answer.
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