Question:
The bond lengths of \( \mathrm{C_2} \), \( \mathrm{N_2} \), and \( \mathrm{B_2} \) molecules are
\( X_1 \), \( X_2 \), and \( X_3 \) pm respectively. The correct order of their bond lengths is:
The bond lengths of \( \mathrm{C_2} \), \( \mathrm{N_2} \), and \( \mathrm{B_2} \) molecules are
\( X_1 \), \( X_2 \), and \( X_3 \) pm respectively. The correct order of their bond lengths is:
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Higher bond order \( \rightarrow \) shorter bond length. Compare using MOT (Molecular Orbital Theory).
Updated On: May 18, 2025
- \( X_3>X_1>X_2 \)
- \( X_2>X_3>X_1 \)
- \( X_1>X_2>X_3 \)
- \( X_1>X_3>X_2 \)
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The Correct Option is A
Solution and Explanation
Bond length \( \propto \) inverse of bond order.
Bond order of B\textsubscript{2} = 1, C\textsubscript{2} = 2, N\textsubscript{2} = 3.
So, bond length order: \( \text{B}_2>\text{C}_2>\text{N}_2 \) or \( X_3>X_1>X_2 \)
Bond order of B\textsubscript{2} = 1, C\textsubscript{2} = 2, N\textsubscript{2} = 3.
So, bond length order: \( \text{B}_2>\text{C}_2>\text{N}_2 \) or \( X_3>X_1>X_2 \)
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