Question:

The Binding energy per nucleon of \(^7_3Li\) and \(^4_2He\) nuclei are 5.60 MeV and 7.06 MeV, respectively. In the nuclear reaction \(^7_3Li + ^1_1H \rightarrow ^4_2He + ^4_2He+Q\), the value of energy Q released is:

Updated On: May 22, 2024
  • -2.4MeV
  • 8.4MeV
  • 17.3MeV
  • 19.6MeV
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

The correct option (C): 17.3MeV
Was this answer helpful?
0
0