Question:
The average power dissipated in a pure capacitance $AC$ circuit is
The average power dissipated in a pure capacitance $AC$ circuit is
Updated On: Jun 6, 2024
- $ CV $
- zero
- $ \frac{1}{CV^{2}} $
- $ \frac{1}{4}CV^{2} $
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The Correct Option is B
Solution and Explanation
Average power in AC circuit is given by
$P=V_{r m s} I_{r m s} \cos \phi$
For pure capacitive circuit $\phi=90^{\circ}$
so $P=0 .$
$P=V_{r m s} I_{r m s} \cos \phi$
For pure capacitive circuit $\phi=90^{\circ}$
so $P=0 .$
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Concepts Used:
AC Voltage
When voltage changes its direction after every half cycle is known as alternating voltage. The current flows in the circuit at that time are known as alternating current. The alternating current(AC) follows the sine function which changes its polarity concerning time. Most of the electrical devices are operating on the ac voltage.
